• UNIT 13 : ELECTROLYSIS

         Key unit competence

     Predict the products of given electrolytes during 
     electrolysis and work out quantitatively to determine how much is liberated at a 

     given electrode using Faraday’s law.  

    Learning Objectives:

    • Define electrolysis, cathode and anode.
    • Explain the electrolysis of different substances.
    • State Faraday’s laws and define the Faraday’s constant.
    • Develop practical experimental skills related to electrolysis, interpret results, 
       and draw valid conclusions.
    • Carry out a practical activity to explain the phenomenon of electrolysis.
    • Compare the electrolysis of dilute solutions and concentrated solutions.
    • Calculate the masses and volumes of substances liberated during electrolysis.
    • Relate the nature of electrode, reactivity of metal ion in solution to the 
       products of electrolysis.

    • Perform electroplating of graphite by copper metal

    Introductory activity

    Observe carefully the figure below and answer the following question. Record your 

    answer and discuss them.

                

     1. Label the set up and give the name of this Experiment.

    2. Suggest how water can be decomposed into hydrogen and oxygen.

      13.1. Definition of electrolysis and Description of electrolytic 

                   cells.

      Activity 13.1:

     A.
        1. In one case, you have a source of water at the top of a hill and you want 
             to supply water to a community in the valley down the hill
        2. In another case, you have a community at the top of a hill and you 
             want to supply water to the community from a source located in the valley 
            down. Students in groups discuss how they would proceed to supply water 
            to the communities in the above two cases. 
     B. Why do we cook food by heating?
    C. What is the difference between a spontaneous reaction and a non
         spontaneous reaction?

    D. Have you heard about electrolysis? If yes, can you say what it is about?

         1.Definition of electrolysis.

    A spontaneous reaction is a reaction that favors the formation of products without 
    external energy. It is a process that will occur on its own. For example, a ball will 
    roll down an incline, water will flow downhill, radioisotopes will decay, and iron will 
    rust. No intervention is required because these processes are thermodynamically 
    favorable.

    A non spontaneous reaction (also called an unfavorable reaction) is a chemical 
    reaction that necessitates external energy to occur. For example, without an 
    external energy source, water will remain water forever. Under the right conditions, 
    using electricity (direct current) will help to produce hydrogen gas and oxygen gas 
    from water. Cooking foods is not spontaneous reaction that is why heat is used.

    Electrolyte: Sodium chloride is an ionic compound in which ions arrange themselves 
    in a rigid cubic lattice when in solid state. In this state, it cannot allow electric current 
    to pass through it. However, when it is melted, or dissolved in water, the rigid lattice 
    is broken, ions are free to move and electric current can pass. Therefore, it is classified 
    as an electrolyte.

    Substances which cannot allow the flow of electric current when in molten or 
    in solution are referred to as non-electrolytes. When electric current (direct 
    current) flows through an electrolyte, it decomposes it. This phenomenon is called 

    electrolysis.

    Thus electrolysis is the decomposition of an electrolyte by passage of an electric 
    current through it. Therefore for electrolysis to take place, there must be a source 
    of direct current. The direct current is conveyed from its source to the electrolyte 
    by means of a metallic conductor and electrodes. The electrode connected to the 
    positive terminal of the direct current is called the anode and the one connected to 
    the negative terminal is the cathode. By convention, the electric current enters the 

    electrolyte by the anode and leaves by the cathode.

    When the current passes through an electrolytic solution, ions migrate and electrons 
    are gained or lost by ions on the electrodes surface. Electrode that is positively 
    charged has deficit of electrons is called anode and the other electrode negatively 
    charged has excess of electrons and is called cathode. Chemical changes at the 

    electrodes due to the passage of electric current are called electrolysis.

    2. Description of electrolytic cells. 

    An electrolytic cell is an electrochemical cell that drives a non-spontaneous redox 
    reaction through the application of external electrical energy. They are often used to 
    decompose chemical compounds, in a process called electrolysis . The Greek word 

    lysis means to break up.

    Important examples of electrolysis are the decomposition of water into hydrogen 
    and oxygen, production of sodium metal, Na, from molten NaCl, production of 
    aluminium and other chemicals. Electroplating (e.g. of copper, silver, nickel or 
    chromium) is done using an electrolytic cell.

    An electrolytic cell has three component parts: an electrolyte and two electrodes 
    (a cathode and an anode). The electrolyte is usually a solution of water or other 
    solvents in which ions are dissolved. Molten salts such as sodium chloride are also 
    electrolytes. When driven by an external voltage applied to the electrodes, the ions 
    in the electrolyte are attracted to an electrode with the opposite charge, where 
    charge-transferring (also called faradaic or redox) reactions can take place. Only 
    with an external electrical potential (i.e. voltage) of correct polarity and sufficient 
    magnitude can an electrolytic cell decompose a normally stable, or inert chemical 
    compound in the solution. The electrical energy provided can produce a chemical 

    reaction which would not occur spontaneously otherwise.

    The main components required to achieve electrolysis are:

    • An electrolyte is substance containing free ions which are the carriers of 
        electric current in the electrolyte. If the ions are not mobile, as in a solid salt 
        then electrolysis cannot occur.
    • A direct current (DC) supply: provides the energy necessary to create or 
       discharge the ions in the electrolyte. Electric current is carried by electronds 
       in the external circuit.
    • Electrolysis depends on controlling the voltage and current.   
    • Alternating current (AC) would not be appropriate for electrolysis.  Because the 
      “cathode” and “anode” are constantly switching places, AC produces explosive 
       mixtures of hydrogen and oxygen.
    • Two electrodes: an electrical conductor which provides the physical interface 

       between the electrical circuit providing the energy and the electrolyte.

                                   

    The key process of electrolysis is the interchange of atoms and ions by the removal 
    or addition of electrons from the external circuit. The products of electrolysis are in 
    some different physical states from the electrolyte and can be removed by some 
    physical processes. 

    Electrodes of metal, graphite and semi-conductor material are widely used. Choice 
    of suitable electrode depends on chemical reactivity between the electrode and 
    electrolyte and the cost of manufacture.

    Note: 
    The suitable electrode in electrolysis should be inert (Cu, Pt, etc.) therefore it will not 
    participate in the chemical reaction.
    It is very easy to be confused about the names CATHODE and ANODE and what their 

    properties are, both with electrochemical cells and electrolytic cells.

    (To help you to remember, Cathode is the site of reduction, or, if you prefer, CCC = Cathode 

    Collects Cations. Anode is the site of oxidation, or, AAA = Anode Attracts Anions.)

    Checking up 13.1:

                  

    13.2. Electrolysis of sodium chloride

      Activity 13.2

    Investigating the effect of concentration on the products formed during 
    electrolysis of concentrated sodium chloride solution.

    Materials: Carbon or graphite rods, connecting wire, U-tube, dry cell, glass 

    syringes, concentrated sodium chloride, cork and switch.

                     

                Figure 13.2.1: Electrolysis of concentrated sodium chloride solution 

    Procedure:

    2. Add 10g of sodium chloride to 100cm3
        of distilled water. 
    3. Warm the mixture and continue adding sodium chloride until a 
         saturated solution is formed.
    4. Put the saturated solution in U-tube and fit it with carbon rods and glass 
        syringes.
    5. Level the brine solution in the two arms and switch on the circuit. 
        Record any observations made after some time. Identify any gases 
        collected in the syringe.

    Questions:
    a. Identify the gases formed by testing them using litmus papers.
    b. Using ionic equations, explain how the products are formed. 

    Sodium chloride may be in different forms that can be electrolytes. It may be in its 
    molten state, dilute solution or concentrated solution. In each case, the products of 
    electrolysis differ because of different factors.

    13.2.1. Electrolysis of molten sodium chloride 

    The molten salt is introduced in a container called electrolytic cell (or electrolysis 
    cell) in which there are two inert electrodes (platinum or graphite). Electrodes are 
    connected to a DC generator. 

              • Cations (Na+) move toward the cathode (negative electrode), where they take 

                  electrons and are reduced. On cathode metallic sodium is deposited: 

                       Figure 13.2.2: Electrolysis of molten sodium chloride solution

    • Another important thing to note is that twice as much hydrogen is produced 
    as oxygen. Thus the volume of hydrogen produced is twice that of oxygen. Refer 

    to the equations above and note the number of electrons involved to help you 

                  13.2.2. Electrolysis of Dilute Sodium Chloride Solution

    An aqueous solution of sodium chloride contains four different types of ions. They 
    are ions from sodium chloride: Na+ (aq) and Cl-(aq)

    Ions from water: H+ (aq) and OH-(aq)

    When dilute sodium chloride solution is electrolysed using inert electrodes, the 
    Na+ and H+ ions are attracted to the cathode. The Cl- and OH- ions are attracted to 

    the anode. 

                                             Table 13.2: Standard reduction potentials.

                  

    The table  shown below  is simply a table of standard reduction potentials in 
    decreasing order. The species at the top have a greater likelihood of being reduced 
    while the ones at the bottom have a greater likelihood of being oxidized. Therefore, 
    when a species at the top is coupled with a species at the bottom, the one at the top 

    will be easily reduced while the one at the bottom will be oxidized.

    • At the cathode:

    The H+ and Na+ ions are attracted to the platinum cathode. H+ ions gains electrons 
    from the cathode to form hydrogen gas. (The hydrogen ions accept electrons more 
    readily than the sodium ions. As a result, H+ ions are discharged as hydrogen gas, 
    which bubbles off. Explanation why  H+ ions are preferentially discharged will be 

    given later.)

                       

    • At the anode:

    OH- and Cl- are attracted to the platinum anode. OH- ions give up electrons to the 

    anode to form water and oxygen gas. 

             

    Adding the two reactions and balancing the terms:

             

    If we remove 2 molecules of water on both sides, we get:

                 

    Note: 

    • Since water is being removed (by decomposition into hydrogen and oxygen), 
    the concentration of sodium chloride solution increases gradually. The overall 
    reaction shows that the electrolysis of dilute sodium chloride solution is 

    equivalent to the electrolysis of water.

                                 

                                                   Figure 13.2.3: Electrolysis of dilute sodium chloride solution

    13.2.3. Electrolysis of Concentrated Sodium Chloride Solution

    The only difference with dilute NaCl solution is that at the anode, Cl-  ions are more 
    numerous than OH- ions. Consequently, Cl- ions are discharged as chlorine gas, which 
    bubbles off. 

    A half-equation shows you what happens at one of the electrodes during 

    electrolysis. 

                               

    Sodium ions Na+ and hydroxide OH– are also present in the sodium chloride 
    solution. They are not discharged at the electrodes. Instead, they make sodium 

    hydroxide solution.

    These products are reactive, so it is important to use inert (unreactive) materials for 

    the electrodes.

    One volume of hydrogen gas is given off at the cathode and one volume of chlorine 
    gas is produced at the anode. The resulting solution becomes alkaline because 

    there are more OH- than H+ ions left in the solution. 

                               

    Checking up 13.2: 

    With the help of equations of reactions which occur at each 
    electrode, outline what happens during electrolysis of dilute aqueous sodium 

    chloride. What happens to the pH of the solution as electrolysis continues?

    13.3. Electrolysis of water

    Activity 13.3: Investigate the products formed during the electrolysis of water

    Materials:

    • Distilled water
    • Tap water
    • 2 silver-colored thumb tacks
    • 9V battery
    • Small, clear plastic container 
    • 2 test tubes
    • Stopwatch
    • Baking soda
    • Table salt
    • Lemon

    • Dish washing detergent

                           

    Procedure:

    3. Insert the thumb tacks into the bottom of the plastic container so that 
    the points push up into the container. Space them so that they’re the 
    same distance apart as the two terminals of the 9V battery. Be careful not 
    to harm yourself!
    4. Place the plastic container with the terminals of the battery. If the cup is 
    too large to balance on the battery, be sure thumb tacks are connect to 
    positive and negative pushpins and do no touch each other.
    5. Slowly fill the container with distilled water. If the tacks move, go ahead 
    and use this opportunity to fix them before you proceed. Will distilled 
    water conduct electricity on its own? Try it!
    6. Add a pinch of baking soda.
    7. Hold two test tubes above each push pin to collect the gas being formed. 
    Record your observations. What happens? Does one tube have more 
    gas than the other? What gases do you think are forming?

    8. Discard the solution, and repeat the procedure with a different 
    combination: 
    • Distilled water and lemon juice
    • Distilled water and table salt
    • Distilled water and dish detergent
    • Distilled water (no additive)
    • Tap water (Does tap water works? If so, why?)

    Question: During the electrolysis of water, which electrolyte conducts 

    electricity the best?

    Water can be decomposed by passing an electric current through it.  When this 
    happens, the electrons from the electric current cause an oxidation-reduction 
    reaction.   At one electrode, called the cathode, electrons cause a reduction.  At the 
    other electrode, called the anode, electrons leave their ions completing the circuit, 
    and cause an oxidation.

    In order to carry out electrolysis the solution  must conduct electric current.  
    Pure water is a very poor conductor.  To make the water conduct better we can 
    add an electrolyte (NaCl) to the water. The electrolyte added must not be more 
    electrolyzable than water.   Many electrolytes that we add electrolyze more easily 
    than water.  Sulfate ions do not electrolyse as easily as water, so sulfates are often 
    used to enhance the conductivity of the water

    Water may be electrolyzed in the apparatus shown below. Pure water is however a 
    very poor conductor of electricity and one has to add dilute sulphuric acid in order 

    to have a significant current flow.

                

    In pure water at the negatively charged cathode, a reduction reaction takes place, 
    with electrons (e−) from the cathode being given to hydrogen cations to form 

    hydrogen gas. The half reaction, balanced with acid, is:

                 Reduction at cathode:

    At the positively charged anode, an oxidation reaction occurs, generating 

    oxygen gas and giving electrons to the anode to complete the circuit:

              Oxidation at anode:

                                               

                 

    Combining either half reaction pair yields the same overall decomposition of water 

    into oxygen and hydrogen:

                 Overall reaction:

    The number of hydrogen molecules produced is thus twice the number of oxygen 
    molecules. Assuming equal temperature and pressure for both gases, the produced 

    hydrogen gas has therefore twice the volume of the produced oxygen gas.

      Checking up 13.3

      I understand the process of water electrolysis, that water as an electrolyte can 
    be decomposed into hydrogen and oxygen via an external energy source (an 
    electrical current). I know that the reduction of hydrogen takes place on the 
    cathode and the oxidation reaction takes place on the anode. I also know 
    that water, already partially split into H+ and OH- (though there are very few 
    of these ions in pure water). 

    1. Electric current (direct current) electrolyzes water. Discuss this 
         statement. 

    2. Why alternative current are not used for the same process?

    13.4. Electrolysis of concentrated copper (II) sulphate solution 

    using inert electrode

    Activity 13.4: Investigating what happens when a solution of copper (II) 

     sulphate is electrolysed using carbon and copper electrodes.

    Apparatus and chemicals: Glass cell, Carbon rod, 2M copper (II) sulphate 
    solution, connecting wires, dry cells, copper plates, propanone and litmus 

    paper.

                         

    Procedure: 

    3. Determine the mass of the graphite rods and record it.
    4. Put 0.5M of copper (II) sulphate solution in a glass cell with the carbon 
        (graphite) rods and set up the apparatus. Carefully observe all the 
        changes taking place at the electrodes and the solution. Test the 
         resulting solution with blue litmus paper.
    5. After some time, switch off the current, remove the electrodes, wash 
        them in propanone, dry then and then weigh them.
    6. Repeat the experiment using clean strips of copper metal as electrodes. 
        Weigh them and then complete the circuit using freshly prepared 

        copper (II) sulphate solution. Record your observations.

    Questions: 
     1. Explain the changes observed during the electrolysis of copper (II)
         sulphate using :

                  a.Carbon electrodes
                  b.Copper electrodes 
    2. Outline the changes that occur in the solution from the beginning 

         to the end of the experiment.

    The products of electrolysing of copper sulphate solution with inert electrodes 

    (carbon/graphite or platinum) are copper metal and oxygen gas.

                        

                         Figure 13.4.1: Simple apparatus to investigate the electrolysis of aqueous solutions

      Using the simple apparatus (diagram above) and inert carbon (graphite) electrodes, 
    you can observe the products of the electrolysis of copper sulfate solution are a 
    copper deposit on the negative cathode electrode and oxygen gas at the positive 
    anode electrode. This anode reaction differs if you use copper electrodes.  You have 
    to fill the little test tubes with the electrolyte (dilute copper sulphate solution), hold 
    the liquid in with your finger and carefully invert them over the nearly full electrolysis 

    cell. The simple apparatus (above) can be used with two inert wire electrodes.

    The blue colour fades as more and more copper is deposited, depleting the 

    concentration of blue copper ion in solution.

    Diagram for the electrolysis of copper (II) sulphate solution with carbon 

    electrodes.

                  

            Figure 13.4.2: The electrolysis of copper (II) sulphate solution with carbon electrodes.

    The electrode reactions and products of the electrolysis of the electrolyte copper 
    sulphate solution (with inert carbon-graphite electrodes) are illustrated by the 

    diagram above

    (a) The electrode products from the electrolysis of copper sulphate with inert 

    graphite (carbon) electrodes

    The negative cathode electrode attracts ions (from copper sulphate) and 
    ions (from water). Only the copper ion is discharged, being reduced into copper 
    metal. The less reactive a metal, the more readily its ion is reduced on the electrode 
    surface.
    A copper deposit forms as the positive copper ions are attracted to the negative 

    electrode (cathode)

    positive ion reduction by electron gain.

    The traces of hydrogen ions are not discharged, so you do not see any gas collected 
    above the negative electrode. The blue colour of the copper ion will fade as the copper 
    ions are converted into the copper deposit on the cathode

    At the positive anode reaction with graphite electrodes

    Oxygen gas is formed at the positive electrode, an oxidation reaction (electron 

    loss).

    The negative sulphate ions or the traces of hydroxide ions  are 
    attracted to the positive electrode. But the sulphate ion is too stable and nothing 

    happens. Instead hydroxide ions are discharged and oxidised to form oxygen.

                           

                                                              Figure 13.4.3: Electrolysis of copper(II) sulphate

    Checking up 13.4

    1. Name the product at the cathode and anode during electrolysis of:
         a. Molten lead bromide with inert electrode.
         b. Acidified copper sulphate solution with inert electrodes.
        c. Acidified water with inert electrode.
        d. Dilute hydrochloric acid with inert electrode.
        e. Concentrated hydrochloric acid with inert electrode.
    2.Predict the products formed when the following molten compounds are 
        electrolysed using carbon electrodes;

         a. Lead(II) bromide

         b. Magnesium oxide

    13.5. Electrolysis of concentrated copper (II) sulphate solution 

            using copper electrodes

    The products of electrolysis of copper sulfate solution with copper electrodes are 
    copper metal and copper ions (the copper anode dissolves).

    The electrolysis of copper (II) sulphate solution using copper electrodes is shown 

    below. 

                              

                              Figure 13.5.1: Electrolysis of copper (II) sulphate

    Using the simple apparatus and two copper electrodes the products of the 
    electrolysis of copper sulphate solution are a copper deposit on the negative 
    cathode electrode and copper dissolves, at the positive anode electrode. 
    This copper anode reaction differs from the one when you use an inert graphite 

    electrode for the anode.

    When Copper (II) sulphate is electrolysed with a copper anode electrode (the 

    cathode can be carbon or copper), the copper deposit on the cathode (–) equals the 

    copper dissolves at the anode (+). Therefore the blue colour of the Cu2+ ions stays 
    constant because Cu deposited = Cu dissolved. Both involve a two electron transfer 
    so it means mass of Cu deposited = mass of Cu dissolving for the same quantity 
    of current flowing (flow of electrons). You can check this out by weighing the dry
    electrodes before and after the electrolysis has taken place.

    The experiment works with a carbon anode and you see the blackness of the graphite 

    change to the orange-brown colour of the copper deposit.

                         

                    Figure 13.5.2: The electrolysis of copper (II) sulphate solution with a copper anode and a 

                    copper cathode.

    The electrode reactions and products of the electrolysis of copper sulphate solution 
    (with a copper anode) are illustrated by the diagram above.

    (a) The electrode products from the electrolysis of copper sulphate with copper 

    electrodes

    The negative cathode electrode attracts ions (from copper sulphate) and 
    ions (from water). Only the copper ion is discharged, being reduced to copper metal.
    A reduction electrode reaction at the negative cathode: 

    (copper deposit, reduction 2 electrons gained) reduction by electron gain.

    The positive anode reaction with copper electrodes
    It’s the copper anode that is the crucial difference than electrolysing copper sulphate 

    solution with an inert carbon (graphite) or platinum electrode.

    The negative sulphate ions  (from copper sulphate) or the traces of hydroxide 
    ions   (from water) are attracted to the positive electrode. But both the sulphate 
    ion and hydroxide ion are too stable and nothing happens to them because the 
    copper anode is preferentially oxidised to discharge  copper ions.

    An oxidation electrode reaction at the positive anode: copper dissolves, two 

    electrons are lost following the half reaction:

                        

    Copper atoms oxidised to copper (II) ions: dissolving of copper in its electrolytic 

    purification or electroplating (must have positive copper anode).

    Copper (II) ions reduced to copper atoms: deposition of copper in its electrolytic 
    purification or electroplating using copper (II) sulphate solution, so the electrode 

    can be copper or other metal to be plated or any other conducting material.

    This means for every copper atom that gets oxidised, one copper ion is reduced, 

    therefore 

    when copper electrodes are used in the electrolysis of copper sulphate solution, the 
    mass loss of copper from the positive anode electrode should equal to the mass of 

    copper gained and deposited on the negative cathode electrode.

    You can show this by weighing both electrodes at the start of the experiment. After 
    the current has passed for some time, carefully extract the electrodes from the 
    solution, wash them, dry them and reweigh them. The gain in mass of the cathode 

    should be the same as the loss of mass from the anode.

    Checking up 13. 5

    1.
         a. Predict the products formed (i) at the cathode, (ii) at the anode, when 
             copper (II) sulphate solution is electrolysed using carbon electrodes.
        b. Describe the colour changes in the electrolyte.
     2. What will you observe
        a. At cathode
        b. At anode
        c. In electrolytic, during the electrolysis of copper (II) sulphate solution 
            with copper electrode.
    3.Write equations for the reaction taking place at cathode and at anode 
          during the electrolysis of:
        a. Acidified copper sulphate solution with copper electrode.
        b. Acidified water with inert electrode.
        c. Molten lead bromide with inert electrode.
    4.Using a table, highlight the similarities and differences between using 
       graphite electrodes and copper electrode for the electrolysis of copper 

       sulphate.

    13.6. Faraday’s Laws

    Activity 13.6

     Comparison of the amounts of different substances liberated by the same 

    quantity of electricity.

                        

                       Figure 13.6: Comparison of the amounts of different substances
                        liberated by the same quantity of electricity

    Set up the circuit containing a copper voltmeter and a silver voltmeter (a 
    voltmeter is a vessel containing two electrodes immersed in a solution of ions 

    through which a current is to be passed.)

    Identify the copper and silver cathodes, clean and dry them, and after weighing 
    them return them in their respective voltmeters. Pass a current of about 0.5A 
    for 20 or 30 minutes, after which the cathodes should be removed, cleaned and 

    dried, and reweighed.

    Compare the masses of copper and silver deposited. Note that care must be 
    taken in removing the silver cathode from the solution as the metal does not 

    always adhere well to the cathode.

    The relationship between the mass of product formed at an electrode and the 
    quantity of electricity passed through an electrolyte is given by Faraday’s laws of 

    electrolysis.

    Michael Faraday (1791-1867) did the first work on electrolysis and formulated what 
    is known today as Faraday’s laws of electrolysis.

    These laws express the quantitative results of electrolysis. They assert that the 
    amount (expressed in moles) of an element liberated during electrolysis depends 

    upon:

          1. The time of passing the steady current, t
          2. The magnitude of the steady current passed, I

         3. The charge of the ions

    13.6.1. Faraday’s first law

    According to this law, “The amount of substance liberated at an electrode is 

    directly proportional to the quantity of electricity passed”

                           

    1F = 96500 coulomb
     So, 1 Faraday [96500 coulomb] of electricity will produce 1 gm equivalent of Ag, 
    Cu and Al at cathode.

    13.6.2. Faraday’s second law 
    According to this law, “if same quantity of electricity is passed through different 
    electrolytes, then the amount of substances liberated at the respective electrodes 

    are in the ratio of their equivalent masses”.

    Or 

    When the same quantity of electricity passes through solutions of different electrolytes, 
    the amounts of the substances liberated at the electrodes are directly proportional to 

    their chemical equivalents.

             

    Equivalent mass is the mass of a substance especially in grams that combines with 
    or is chemically equivalent to eight grams of oxygen or one gram of hydrogen; the 

    atomic or molecular Mass divided by the valence.

    Example: 
    Calculate the amount of electric charge in coulombs which can 
    deposit 5.2g of aluminium when a current was passed through a solution of 

    aluminium sulphate for some time.

    Solution:

    3 moles of electrons are needed to deposit 1 mole of aluminium (24g of 

    aluminium).

    Checking up 13.6

    1. A current of 0.65A was passed through sulphate solution of metal X 
         for 35 minutes between platinum electrodes. If 0.449 g of the metal is 
        deposited at the cathode, calculate the charge on the element X (atomic 
         mass is 63.5)

    2. When a constant current was passed through an aqueous solution 
        of copper (II) nitrate for one hour the mass of the copper cathode 
       increased by 15.24 g. Calculate the current in amperes which was used( 

       F= 96500 Cu = 63.5)

    13.7. Factors affecting Electrolysis

    Activity13.7: Investigating how the nature of electrodes affects the discharge                                                                                              of ions during electrolysis.
    Apparatus and chemicals: 
    • Beaker (100 cm3)
    • 6V Battery
    • 2 connecting wires with crocodile clips
    • 2 carbon electrodes
    • 2 copper electrodes
    •   solution
    Caution: Do not allow the electrodes to touch each other while the power 

    supply is switched on, otherwise this may damage the equipment.

    A. Electrolysing of copper (II) sulphate solution using Carbon electrodes.

                     

              Figure 13.7.1: Electrolysis of copper (II) sulphate solution using carbon electrodes.

     Procedure: let the current flow for 5 minutes

     Observe what happens at each electrode

    Questions:

    1. What product is formed on the cathode?
    2. What product is formed at the anode?
    3. Has the colour of the solution changed?

    4. Explain the observations in 3.

    B.Electrolysing of copper(II) sulphate solution using Copper electrodes 
                                      

    Procedure: let the current flow for 5 minutes

     Observe what happens at each electrode


    Questions:

    1. What product is formed on the cathode?
    2. What product is formed at the anode?
    3. Has the colour of the solution changed?

    4. Explain the observations in 3.

    In an electrolysis where there are more than one species which can be discharged 
    at the same electrode, only one of them is discharged at a time; for example, in an 
    aqueous sodium chloride solution, we have four species that is, and 
     ions from sodium chloride and and ions from water.
    During electrolysis ions and ions migrate to the cathode while   ions and 
       migrate to the anode.
    Now the question is, which species of ions will be discharged at the cathode and 
    which ones will be discharged at the anode first?

    The factors which decide the selective discharge of ions are:

    • Nature of electrodes
    • Position of the ion in electrochemical series
    • Concentration 

    • The state of the electrolyte

    13.7.1. Nature of Electrodes

    In the electrolysis of sodium chloride solution using a platinum cathode, ions 

    are discharged first in aqueous solution.

           

    However, if the cathode is mercury, sodium is discharged. The sodium atom 

    discharged combines with mercury cathode to form sodium amalgam.

                 

      Electrolysis of copper sulphate using copper anode  

    In this electrolysis, the anions,   migrate to the anode but none of them 

    is discharged. Instead the copper atoms of the anode ionise and enter the solution.

                     

    The copper (II) ions are attracted to the cathode and copper is deposited as a brown 

    layer. The use of platinum anode gives oxygen as the product due to the reaction;

                 

    13.7.2. Position of ion in Electrochemical Series

    When solving for the standard cell potential, the species oxidized and the species 
    reduced must be identified. This can be done using the activity series. The table 13.2 
    is simply a table of standard reduction potentials in decreasing order. The species 
    at the top have a greater likelihood of being reduced while the ones at the bottom 
    have a greater likelihood of being oxidized. Therefore, when a species at the top is 
    coupled with a species at the bottom, the one at the top will become reduced while 

    the one at the bottom will become oxidized. 

    During electrolysis of solution containing a mixture of ions, the ion lower in 

    electrochemical series is discharged first in preference to the one high in the series.

    Let us look at the role of water in electrolysis products.

    Water molecules to a small extent (degree) ionize as

                

    Due to the above ionization, aqueous solutions of electrolytes contain two sets 
    of ions that is those from the salt dissolved and the   ions from water 

    molecules.

     Example:

    Electrolysis of aqueous copper (II) sulphate solution using platinum electrodes.

    Ions present in solution:

                    

           Cathode

          

              The cathode gets coated with a brown layer of copper as the solution loses its blue 

               colour.

               Anode 

               

    13.7.3. Concentration of electrolyte solution

    Increase of concentration of an ion tends to promote its discharge, for example in 
    concentrated hydrochloric acid, containing 
     as negative ions, the highly concentrated  is discharged in preference.

    However, if the acid is very dilute, some discharge of will also occur. It is important 
    to know that as the acid is diluted, there will not be a point at which chlorine ceases 
    to be produced and oxygen replaces it. Instead a mixture of the two gases will come 

    off, with the proportion of oxygen gradually increasing.

    Another case in which the order of discharge according to the electrochemical series 
    is reversed by a concentration effect is that of sodium chloride solution.

    In concentrated solution of sodium chloride called brine, the following reactions 
    occur.
                  

    Question 3

    A university student set up three different electrolytic cells. The substances that 
    were electrolysed were NaCl (l), 0.05 M NaCl (aq) and 5.0 M NaCl (aq). Which of 
    the following statements correctly describes the results of the experiment? 

    a. The reactions occurring for the aqueous solutions will produce the same 
         products at the anode and cathode. 
    b. Chlorine gas is the major product when molten NaCl (aq) and 0.05 M 
         NaCl (aq) are electrolysed. 
    c. The pH at the cathode increases when solutions of NaCl are electrolysed. 
    d. The only means by which different products can be produced for 

         varying concentrations of NaCl is to alter the voltage.

    13.7.4. The state of the electrolyte

    The half reactions taking place at the electrode depends on whether the electrolyte 
    is in a molten or an aqueous state, and if in aqueous state its concentration. For 
    example, the electrode reactions that take place during the electrolysis of molten 

    potassium iodide are:

               

    However, if aqueous potassium iodide is used, the following electrode reactions 
    take place:
                
                                                  Electrode signs and reactions

                 

     Checking up 13.7

    Question 1 

    A student set up the following experiment. How would the rate of electrolysis 

    in beaker 2 compare to that in beaker 1?

                               

    13.8. Application of electrolysis

    Activity 13.8 

    Copper-Plated Key

    Materials:

    • 1.5-volt D battery with battery holder
    • Two alligator clip leads or insulated wire
    • Beaker or glass
    • Copper sulphate
    • Copper electrode (or coil of copper wire)
    • Brass key

    • Safety equipment

    Procedure:

    5. Prepare the key for copper-plating by cleaning it with toothpaste or 
        soap and water. Dry it off on a paper towel.
    6. Stir copper sulphate into some hot water in a beaker until no more will 

        dissolve. Your solution should be dark blue. Let it cool.

    3. Use one alligator clip to attach the copper electrode to the positive terminal 
         of the battery (this is now the anode) and the other to attach the key to the 
        negative terminal (now called the cathode).

    4. Partially suspend the key in the solution by wrapping the wire lead loosely 
        around a pencil and placing the pencil across the mouth of the beaker. The 
         alligator clip should not touch the solution.

    5. Place the copper strip into the solution, making sure it doesn’t touch the key 
         and the solution level is below the alligator clip. An electrical circuit has now 
        formed and current is flowing.

    6. Leave the circuit running for 20-30 minutes, or until you are happy with the 
         amount of copper on the key.

    Question: Observe carefully electrolysis process and records what happened 

    during the electrolysis process.

    Electrolysis has a number of important industrial applications. These include 
    the extraction and purification of metals, electroplating and anodizing and the 

    manufacture of other chemicals for example sodium hydroxide (NaOH).

    Extraction of metals

    Metals in group I and II of the periodic table cannot be reduced by chemical 
    reducing agents; they are extracted from their fused halides by electrolysis. Sodium 
    is obtained by electrolysis of molten sodium chloride in the Dawncell. Magnesium is 
    obtained by electrolysis of  genera ted from dolomite and sea water.
    Extraction of aluminum

    The chief ore of aluminum is bauxite, it contains silica and iron (III) 

    oxide as impurities. Bauxite is dissolved in a strong solution of sodium hydroxide:

                 

    The impurities are not affected by the presence of sodium hydroxide because they 
    are not amphoteric and they are thus filtered off. The solution is diluted, cooled and 

    seed by adding a few crystals of pure Al 

    On seeding, the aqueous tetrahydroxoaluminate is precipitated as pure Al

    from the solution:

                              

    The electrolytic cell is an iron tank lined with carbon, which acts as the cathode. The 
    anodes are blocks of carbon dipped into the electrolyte. The electrolyte is a solution 
    of molten aluminum oxide in molten cryolite. Cryolite acts as a solvent to dissolve 
    aluminum oxide and as an impurity to lower the melting point of aluminum oxide. 

    The electrolytic cell is maintained at around 900°C.

                      

    Aluminum ions are discharged at the cathode, forming a pool of molten aluminum 
    at the bottom of the tank.

    At high temperature, oxygen reacts with the carbon anode to form carbon dioxide 
    gas. Hence, the anodes are slowly burnt away as carbon dioxide gas and needs to be 

    replaced frequently.

    Manufacture of NaOH and extraction of  gas in Downcell

    Construction of Down’s cell 

    • Down’s cell consists of a rectangular container of steel.
    • Inside of the tank is lined with firebricks.
    • Anode is a graphite rod which projects centrally up through the base of the 
       cell.
    • Cathode is a ring of iron, which surrounds the anode
         The anode and cathode are separated from each other by a cylindrical steel 
         gauze diaphragm; so that and are kept apart.

    • A bell like hood is submerged over the anode

                 

                
    These are manufactured by electrolysis of concentrated sodium chloride, called 

    brine. Hydrogen is also obtained as by products. In solution, sodium chloride ionizes:

           

    Using carbon electrodes, the products of electrolysis are chlorine at the anode and 

    hydrogen at the cathode. Hydrogen is discharged in preference to sodium.

               

    The sodium discharged at the mercury cathode forms a solution of sodium amalgam 
    in mercury. The sodium amalgam is collected in a reservoir in which it reacts 
    with water to form sodium hydroxide solution and hydrogen gas. Mercury is also 

    recovered and returned to the electrolytic cell to pass through the process again.

          

    The sodium hydroxide produced is crystallized. It is used in:
    • Manufacture of soap
    • The paper industry-wood contains lignin, which is a nitrogenous compound, in 
    addition to cellulose. Wood chips are converted into pulp by boiling the chips 
    with sodium hydroxide solution to remove the lignin. The digested material is 

    bleached with chlorine.

    Purification of metals

    Metals such as copper, zinc and aluminium can be purified by electrolysis. The 
    purification of metals is known as refining. The copper obtained after the reduction 
    process is not very pure. It contains small amounts of impurities such as iron. This 
    copper is called blister copper and is refined by an electrolytic method. It is cast 

    into bars which are used as anodes in acidified copper (II) sulphate solution.

    The cathode is made of thin pure copper. During the electrolysis, ions are 
    transferred from the anode to the cathode where they are discharged and copper is 

    deposited.

                

    The net effect is to dissolve the anode made of impure copper and thicken the 

    cathode (pure copper) with more pure copper.

    Electroplating

    This is a process of coating a metal with another of interest mainly to prevent it from 
    rusting, or/ and to improve its appearance, for example, in silver plating articles as 
    cake dishes, made of base alloy, for example cupronickel, are made the cathode in 
    plating bath of potassium (or sodium) dicyanoargentate(I), solution. This 
    contains some silver ions, The anode is pure silver. When direct current passes, 

    the following reactions occur.

           

    In general;

    • The metal being coated is made the cathode and the metal coating is the anode 
    • The solution used is made of the ions of a metal that is coating, so that the 

        anode can dissolve. Anode is the pure plating metal.

                     

     A good electroplating requires steady electric current, appropriate concentration of 

    electrolyte and temperature. The metal to electroplate must be clean.

    Checking up 13.8

    1. a. What is the difference between electrolytic extraction of a metal and 
              electroplating?
        b. Draw a set up used to electroplate a spoon by silver.
    2.What is the material for cathode and anode during electro refining of impure 
            copper? 

    3. Electrometallurgy is the process of reduction of metals from metallic 
         compounds to obtain the pure form of metal. Given elements: aluminum, 
         lithium, sodium, potassium, magnesium, calcium, Zinc, Iron and copper 
         which ones can be reduced by chemical agents such as carbon and which 

         ones are produced by electrolysis only?

    13.9. End Unit Assessment

    1. Choose from a list of words and fill in the missing words in the text below: 
          electrolysis, cathode and anode. When the current passes through an 
           electrolytic solution, ions migrate and electrons are gained or lost by ions 
          on the electrodes surface. Electrode that is positively charged has deficit 
          of electrons is called…………and other negatively charged has excess of 
          electrons is called……………. chemical changes at the electrodes due to the 
           passage of electric current are called ………………...

    2. Answer by true or false
          a. The Avogadro (1791-1867) did the first work on electrolysis and 
             formulated what is known today as faraday’s laws of electrolysis.
         b. Electroplating is a process of coating a metal with another of interest 
             mainly to prevent it from rusting, and to improve its appearance.
         c. A non electrolyte is a solution or molten compound which cannot be 
            decomposed by an electric current.
        d. An ion is an atom or a group of atoms (radical) which has an electric 
           charge.
      e. An anode is the negative electrode through which electrons leave 
           the electrolyte and a cathode is the positive electrode through which 
            electrons enter the electrolyte or leave the external circuit.

    3. Which of the following involves electrolysis?
          a. Photosynthesis and Respiration
          b. Purification of Copper and Sea Water
          c. Purification of copper and extraction of reactive metals 
         d. Extraction of reactive metals and Respiration

    4. Which of the following is not an inert electrode? 
            a. Carbon 
            b. Copper
            c. Platinum 
            d. Mercury 

    5. What ions are present in the electrolysis of aqueous Copper (II) Sulfate with 
             Copper electrodes?
         a. Copper (II) ions, Sulfate ions
         b. Hydrogen ions, Oxygen ions, Copper (II) ions
         c. Copper (II)ions
         d. Hydrogen ions, Hydroxide ions, Copper (II) ions, Sulfate ions

    6. What happens during the electrolysis of a diluted sodium chloride solution?
    a. Hydrogen ions and chlorine ions are discharged.
    b. Hydrogen ions and hydroxide ions are discharged.
    c. Sodium ion and chlorine ions are discharged.
    d. Sodium ions and hydroxide ions are discharged.

    7. State three applications of electrolysis on a large scale and describe one of 
    them briefly.

    8. Describe how the factor of concentration affects electrolysis.

    9. Calculate the amount of electricity required (in Faradays) to deposit one mole 
    of lead ions if a current of 2.5A was passed for 20 minutes through molten lead 
    (II) bromide and 3.20 g of lead metal was deposited.
     

    10. An element X has a relative atomic mass of 88. When a current of 0.5A is 
         passed through the molten chloride of X for 32 minutes and 10 seconds, 0.44 
         g of X deposited at the electrode.

        • Calculate the number of Faradays needed to liberate 1 mol of X.

        • Write the formula of the ion of X (1F= 96500C).

    UNIT 12: CONDUCTIVITY OF SOLUTIONSUNIT 14: ENTHALPY CHANGE OF REACTIONS